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Mickey · 17/12/2008 07:46 PM

Code:

http://www.algebrahelp.com/calculators/expression/factoring/calc.do?expression=(x-h)(x-h)

Quote:Combine like terms: -1hx + -1hx = -2hx
(-2hx + 1h2 + x2)

by the way 1h2 is h^2

Kaiser · 17/12/2008 07:57 PM

sorry, my bad

didn't realized you wrote (x-h)(x-h) >_>

i saw a (x+h)(x-h) which would be a difference of squares

Mickey · 17/12/2008 07:59 PM

Kaiser Wrote:sorry, my bad

didn't realized you wrote (x-h)(x-h) >_>

i saw a (x+h)(x-h) which would be a difference of squares

if only i remembered this poo poo during my finals Sadcorner

Slushba132 · 17/12/2008 08:06 PM

yes

kaiser and mickey are both right I guess...
or I think...

I am too lazy to go back and figure out just who is right...
I eventually figured it out

I did what kaisers did
but I'm sure mick3ys works too

e-pigs for everyone!!!!

diego · 17/12/2008 08:18 PM

I hated quadratics. Enjoy physics more.

roberth · 17/12/2008 08:35 PM

I hated lessons....enjoyed lunchtime more

osnap1584 · 17/12/2008 09:05 PM

Anyone want to find the integral of (x+5)/[(x-1)(x+2)] ?

Slushba132 · 17/12/2008 09:28 PM

I do not know what an integral is...

osnap1584 · 17/12/2008 09:38 PM

just playing you'll learn it when you take calculus. the answer to my question has logs by the way. Basically it is used o find the area under the curve of a graph. I haven't really grasped the concept itself but it's used a lot in physics as well.

Assassinator · 18/12/2008 12:38 AM

Slushba132 Wrote:solve for "a"...

or at least find x, y, h and k in terms of a

so
a = ""

50 e-pigs for the person who does it correctly

You mean... find a in terms of x, y, h and k... right?

Heh, way too easy.

osnap1584 Wrote:Anyone want to find the integral of (x+5)/[(x-1)(x+2)] ?

Harder than Slushie's one. But pretty trivial if you know what you're doing.

Use partial fraction decomposition.

∫(x+5)/[(x-1)(x+2)]= ∫[A/(x-1)+B/(x+2)]

Ax+2A+Bx-B = x+5
=> A=2, B=-1.

∫(x+5)/[(x-1)(x+2)]
=∫[2/(x-1)-1/(x+2)]
=2ln(x-1)-ln(x+2)+C.

Threaded Mode \| Linear Mode y=a(x-h)^2+k
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