ZiNgA BuRgA
Smart Alternative
Posts: 17,022.2988 Threads: 1,174
Joined: 19th Jan 2007
Reputation: -1.71391
E-Pigs: 446.1274
|
RE: Math Help!
Probably best to see your teachers/tutors if you're struggling at that level.
|
|
09/11/2010 05:01 PM |
|
Assassinator
...
Posts: 6,646.6190 Threads: 176
Joined: 24th Apr 2007
Reputation: 8.53695
E-Pigs: 140.8363
|
RE: Math Help!
(08/11/2010 08:29 PM)theEvilOne Wrote: Here wee go,
1.) If P is the principal, or amount borrowed, i, is the monthly interest rate (as a decimal), and n is the number of monthly payments, then the amount, A, of each monthly payment is:
Pi
A= ___________ (Read as: A equals Pi over 1 minus 1 over (1+i) raised to the nth)
1 - 1
_______
(1+i)^n
a.) Simplify the complex rational expression for the amount of each payment.
b.) You purchased a $30,000 car at 1% monthly interest to be paid over 48 months. How much do you pay each month? round to the nearest dollar.
Are you sure you copied that right?
I have never seen an anuity formula which requires Pi. I have never seen any formula in finance that requires Pi. Pi is related to geometry (angles, circles, that kind of shit). Finance is fucking money. F UCK, write P*i instead of Pi.
Then it should be trivial, no tricks or anything at all. Just stick the numbers into the formula, get answer.
I can see why Zinga refused to help you. And I will do so for the same reason.
(09/11/2010 04:49 PM)theEvilOne Wrote: Give me an equation and I'll do just fine, but give me a word problem and it'll fudge me in the donkey.
They already gave you the formula. Which you can apply without any further mathematical manipulation. What more do you want?
(08/11/2010 08:29 PM)theEvilOne Wrote: 2.) Use synthetic division and the remainder theorem to show that 2 is a zero of y=x^3-4x^2+x+6. Find the remaining zeros.
Don't know what the f uck you need to do with the remainder theorem. I don't even remember what the remainder theorm is any more...
But to solve that, since they already told you 2 is a root... just divide that whole thing by (x-2), then you end up with an order 2 polynomial (quadratic) which you can factorize via standard methods.
(This post was last modified: 09/11/2010 06:10 PM by Assassinator.)
|
|
09/11/2010 05:39 PM |
|