Nah, you'd just have to grab the height component and substitute it into the volume formula I'd imagine.

Actually, I think my algebra's comming back to me:
(where r₁ is the radius of the base)
r = (h² + r₁²)/(2h)
2hr = h² + r₁²
h² - 2hr + r₁² = 0

h = (2r ± √4r² - 4r₁²) / 2
= r ± √r² - r₁²

In this case, r > h, so the ± is probably a -

Plug h into volume formula:
V = (Pi/6)(3r₁² + h²)h

EDIT: I'm not sure your thing exactly works cause you're introducing more variables?

(This post was last modified: 11/10/2011 10:55 PM by ZiNgA BuRgA.)