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osnap1584
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Post: #17

RE: y=a(x-h)^2+k

Anyone want to find the integral of (x+5)/[(x-1)(x+2)] ?

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17/12/2008 09:05 PM

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Messages In This Thread

y=a(x-h)^2+k - Slushba132 - 17/12/2008, 05:41 PM

RE: y=a(x-h)^2+k - Mickey - 17/12/2008, 06:09 PM

RE: y=a(x-h)^2+k - roberth - 17/12/2008, 06:27 PM

RE: y=a(x-h)^2+k - Mickey - 17/12/2008, 06:36 PM

RE: y=a(x-h)^2+k - feinicks - 17/12/2008, 07:28 PM

RE: y=a(x-h)^2+k - Kaiser - 17/12/2008, 07:30 PM

RE: y=a(x-h)^2+k - Mickey - 17/12/2008, 07:32 PM

RE: y=a(x-h)^2+k - Kaiser - 17/12/2008, 07:32 PM

RE: y=a(x-h)^2+k - Mickey - 17/12/2008, 07:34 PM

RE: y=a(x-h)^2+k - Kaiser - 17/12/2008, 07:37 PM

RE: y=a(x-h)^2+k - Mickey - 17/12/2008, 07:46 PM

RE: y=a(x-h)^2+k - Kaiser - 17/12/2008, 07:57 PM

RE: y=a(x-h)^2+k - Mickey - 17/12/2008, 07:59 PM

RE: y=a(x-h)^2+k - Slushba132 - 17/12/2008, 08:06 PM

RE: y=a(x-h)^2+k - diego - 17/12/2008, 08:18 PM

RE: y=a(x-h)^2+k - roberth - 17/12/2008, 08:35 PM

RE: y=a(x-h)^2+k - osnap1584 - 17/12/2008 09:05 PM

RE: y=a(x-h)^2+k - Slushba132 - 17/12/2008, 09:28 PM

RE: y=a(x-h)^2+k - osnap1584 - 17/12/2008, 09:38 PM

RE: y=a(x-h)^2+k - roberth - 18/12/2008, 06:10 AM

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