well here is the problem figure it out
ok if your all bored here is a little problem for u all to solve
u get 100 epigs
with the hundred epigs u have to buy 3 objects
object A cost 0.5 epigs
object B costs 3 epigs
object c costs 10 epigs

u have to buy 100 among all the objects with exactly 100 epigs n u have to buy atleast 1 object of each category
so the total number of objects bought and the total number of epigs spent should be exactly 100
now tell me how many objects do u have to buy of each type

10 B's = 30
20 A's = 10
60 C's = 60

that should be about right.

(This post was last modified: 23/01/2008 05:59 PM by Sparker.)

70 + 30 + 10 ≠ 100

OH SHI-

Oh right it's fixed now

just to be different:
object c x1@10 = 10
object b x1@3 = 3
object a x174@0.5 = 87
:P

Math should be kept off the internet. XD

Sparker Wrote:OH SHI-

Oh right it's fixed now

60 + 20 + 10 ≠ 100

Quote:u have to buy 100 among all the objects with exactly 100 epigs n u have to buy atleast 1 object of each category

Whoops almost forgot something.

Quote:object c costs 10 epigs

Sparker Wrote:60 C's = 60

Almost got it. :P
4 C's = 40
5 B's = 15
90 A's = 45

99 Objects, 100 e-pigs. Soooo close!

(This post was last modified: 23/01/2008 07:23 PM by michaelp.)

E=MC2