ZiNgA BuRgA Wrote: [ -> ]theEvilOne Wrote: [ -> ]ZiNgA BuRgA Wrote: [ -> ]theEvilOne Wrote: [ -> ]a.) Simplify the complex rational expression for the amount of each payment.
Don't think you can, as that expression looks like a rearrangement of the present value of annuity formula.
theEvilOne Wrote: [ -> ]b.) You purchased a $30,000 car at 1% monthly interest to be paid over 48 months. How much do you pay each month? round to the nearest dollar.
C'mon, you should be able to do this one at least. (if not, why are you taking the course again?)
Forgot how to factor things.
I'm taking it again because it's a required class and I failed it the first time around.
I'm an English major so this math spoon is useless to me.
It's just plugging numbers into a formula. You got to be able to do that - barely harder than year 8 maths. They'll easily get you on a test if you can't even do that.
Give me an equation and I'll do just fine, but give me a word problem and it'll fudge me in the donkey.
Probably best to see your teachers/tutors if you're struggling at that level.
theEvilOne Wrote: [ -> ]Here wee go,
1.) If P is the principal, or amount borrowed, i, is the monthly interest rate (as a decimal), and n is the number of monthly payments, then the amount, A, of each monthly payment is:
Pi
A= ___________ (Read as: A equals Pi over 1 minus 1 over (1+i) raised to the nth)
1 - 1
_______
(1+i)^n
a.) Simplify the complex rational expression for the amount of each payment.
b.) You purchased a $30,000 car at 1% monthly interest to be paid over 48 months. How much do you pay each month? round to the nearest dollar.
Are you sure you copied that right?
I have never seen an anuity formula which requires Pi. I have never seen any formula in finance that requires Pi. Pi is related to geometry (angles, circles, that kind of shit). Finance is fucking money. F
UCK, write P*i instead of Pi.
Then it should be trivial, no tricks or anything at all. Just stick the numbers into the formula, get answer.
I can see why Zinga refused to help you. And I will do so for the same reason.
theEvilOne Wrote: [ -> ]Give me an equation and I'll do just fine, but give me a word problem and it'll fudge me in the donkey.
They already gave you the formula. Which you can apply without any further mathematical manipulation. What more do you want?
theEvilOne Wrote: [ -> ]2.) Use synthetic division and the remainder theorem to show that 2 is a zero of y=x^3-4x^2+x+6. Find the remaining zeros.
Don't know what the f
uck you need to do with the remainder theorem. I don't even remember what the remainder theorm is any more...
But to solve that, since they already told you 2 is a root... just divide that whole thing by (x-2), then you end up with an order 2 polynomial (quadratic) which you can factorize via standard methods.